Optimal. Leaf size=193 \[ -\frac {x^3 \left (48 A b^2-a (a C+6 b B)\right )}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {x (8 A b-a B)}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {x^5 \left (192 A b^3-a \left (3 a^2 D+4 a b C+24 b^2 B\right )\right )}{15 a^4 \left (a+b x^2\right )^{7/2}}-\frac {x^7 \left (384 A b^4-a \left (15 a^3 F+6 a^2 b D+8 a b^2 C+48 b^3 B\right )\right )}{105 a^5 \left (a+b x^2\right )^{7/2}}-\frac {A}{a x \left (a+b x^2\right )^{7/2}} \]
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Rubi [A] time = 0.34, antiderivative size = 193, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 37, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.108, Rules used = {1803, 1813, 12, 264} \[ -\frac {x^7 \left (384 A b^4-a \left (6 a^2 b D+15 a^3 F+8 a b^2 C+48 b^3 B\right )\right )}{105 a^5 \left (a+b x^2\right )^{7/2}}-\frac {x^5 \left (192 A b^3-a \left (3 a^2 D+4 a b C+24 b^2 B\right )\right )}{15 a^4 \left (a+b x^2\right )^{7/2}}-\frac {x^3 \left (48 A b^2-a (a C+6 b B)\right )}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {x (8 A b-a B)}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {A}{a x \left (a+b x^2\right )^{7/2}} \]
Antiderivative was successfully verified.
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Rule 12
Rule 264
Rule 1803
Rule 1813
Rubi steps
\begin {align*} \int \frac {A+B x^2+C x^4+D x^6+F x^8}{x^2 \left (a+b x^2\right )^{9/2}} \, dx &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {\int \frac {8 A b-a \left (B+C x^2+D x^4+F x^6\right )}{\left (a+b x^2\right )^{9/2}} \, dx}{a}\\ &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {(8 A b-a B) x}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {\int \frac {x^2 \left (6 b (8 A b-a B)+a \left (-a C-a D x^2-a F x^4\right )\right )}{\left (a+b x^2\right )^{9/2}} \, dx}{a^2}\\ &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {(8 A b-a B) x}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {\left (48 A b^2-a (6 b B+a C)\right ) x^3}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {\int \frac {x^4 \left (4 b \left (48 A b^2-6 a b B-a^2 C\right )+3 a \left (-a^2 D-a^2 F x^2\right )\right )}{\left (a+b x^2\right )^{9/2}} \, dx}{3 a^3}\\ &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {(8 A b-a B) x}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {\left (48 A b^2-a (6 b B+a C)\right ) x^3}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {\left (192 A b^3-a \left (24 b^2 B+4 a b C+3 a^2 D\right )\right ) x^5}{15 a^4 \left (a+b x^2\right )^{7/2}}-\frac {\int \frac {\left (2 b \left (192 A b^3-24 a b^2 B-4 a^2 b C-3 a^3 D\right )-15 a^4 F\right ) x^6}{\left (a+b x^2\right )^{9/2}} \, dx}{15 a^4}\\ &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {(8 A b-a B) x}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {\left (48 A b^2-a (6 b B+a C)\right ) x^3}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {\left (192 A b^3-a \left (24 b^2 B+4 a b C+3 a^2 D\right )\right ) x^5}{15 a^4 \left (a+b x^2\right )^{7/2}}-\frac {\left (384 A b^4-48 a b^3 B-8 a^2 b^2 C-6 a^3 b D-15 a^4 F\right ) \int \frac {x^6}{\left (a+b x^2\right )^{9/2}} \, dx}{15 a^4}\\ &=-\frac {A}{a x \left (a+b x^2\right )^{7/2}}-\frac {(8 A b-a B) x}{a^2 \left (a+b x^2\right )^{7/2}}-\frac {\left (48 A b^2-a (6 b B+a C)\right ) x^3}{3 a^3 \left (a+b x^2\right )^{7/2}}-\frac {\left (192 A b^3-a \left (24 b^2 B+4 a b C+3 a^2 D\right )\right ) x^5}{15 a^4 \left (a+b x^2\right )^{7/2}}-\frac {\left (384 A b^4-a \left (48 b^3 B+8 a b^2 C+6 a^2 b D+15 a^3 F\right )\right ) x^7}{105 a^5 \left (a+b x^2\right )^{7/2}}\\ \end {align*}
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Mathematica [A] time = 0.19, size = 138, normalized size = 0.72 \[ \frac {a^4 \left (-105 A+105 B x^2+35 C x^4+21 D x^6+15 F x^8\right )+2 a^3 b x^2 \left (-420 A+105 B x^2+14 C x^4+3 D x^6\right )+8 a^2 b^2 x^4 \left (-210 A+21 B x^2+C x^4\right )+48 a b^3 x^6 \left (B x^2-28 A\right )-384 A b^4 x^8}{105 a^5 x \left (a+b x^2\right )^{7/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.02, size = 187, normalized size = 0.97 \[ \frac {{\left ({\left (15 \, F a^{4} + 6 \, D a^{3} b + 8 \, C a^{2} b^{2} + 48 \, B a b^{3} - 384 \, A b^{4}\right )} x^{8} + 7 \, {\left (3 \, D a^{4} + 4 \, C a^{3} b + 24 \, B a^{2} b^{2} - 192 \, A a b^{3}\right )} x^{6} - 105 \, A a^{4} + 35 \, {\left (C a^{4} + 6 \, B a^{3} b - 48 \, A a^{2} b^{2}\right )} x^{4} + 105 \, {\left (B a^{4} - 8 \, A a^{3} b\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{105 \, {\left (a^{5} b^{4} x^{9} + 4 \, a^{6} b^{3} x^{7} + 6 \, a^{7} b^{2} x^{5} + 4 \, a^{8} b x^{3} + a^{9} x\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.60, size = 220, normalized size = 1.14 \[ \frac {{\left ({\left (x^{2} {\left (\frac {{\left (15 \, F a^{13} b^{3} + 6 \, D a^{12} b^{4} + 8 \, C a^{11} b^{5} + 48 \, B a^{10} b^{6} - 279 \, A a^{9} b^{7}\right )} x^{2}}{a^{14} b^{3}} + \frac {7 \, {\left (3 \, D a^{13} b^{3} + 4 \, C a^{12} b^{4} + 24 \, B a^{11} b^{5} - 132 \, A a^{10} b^{6}\right )}}{a^{14} b^{3}}\right )} + \frac {35 \, {\left (C a^{13} b^{3} + 6 \, B a^{12} b^{4} - 30 \, A a^{11} b^{5}\right )}}{a^{14} b^{3}}\right )} x^{2} + \frac {105 \, {\left (B a^{13} b^{3} - 4 \, A a^{12} b^{4}\right )}}{a^{14} b^{3}}\right )} x}{105 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}}} + \frac {2 \, A \sqrt {b}}{{\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} - a\right )} a^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 166, normalized size = 0.86 \[ -\frac {384 A \,b^{4} x^{8}-48 B a \,b^{3} x^{8}-8 C \,a^{2} b^{2} x^{8}-6 D a^{3} b \,x^{8}-15 F \,a^{4} x^{8}+1344 A a \,b^{3} x^{6}-168 B \,a^{2} b^{2} x^{6}-28 C \,a^{3} b \,x^{6}-21 D a^{4} x^{6}+1680 A \,a^{2} b^{2} x^{4}-210 B \,a^{3} b \,x^{4}-35 C \,a^{4} x^{4}+840 A \,a^{3} b \,x^{2}-105 B \,a^{4} x^{2}+105 A \,a^{4}}{105 \left (b \,x^{2}+a \right )^{\frac {7}{2}} a^{5} x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.54, size = 421, normalized size = 2.18 \[ -\frac {F x^{5}}{2 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b} - \frac {5 \, F a x^{3}}{8 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b^{2}} - \frac {D x^{3}}{4 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b} + \frac {16 \, B x}{35 \, \sqrt {b x^{2} + a} a^{4}} + \frac {8 \, B x}{35 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{3}} + \frac {6 \, B x}{35 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} a^{2}} + \frac {B x}{7 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} a} + \frac {F x}{14 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} b^{3}} + \frac {F x}{7 \, \sqrt {b x^{2} + a} a b^{3}} + \frac {3 \, F a x}{56 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} b^{3}} - \frac {15 \, F a^{2} x}{56 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b^{3}} + \frac {3 \, D x}{140 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} b^{2}} + \frac {2 \, D x}{35 \, \sqrt {b x^{2} + a} a^{2} b^{2}} + \frac {D x}{35 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a b^{2}} - \frac {3 \, D a x}{28 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b^{2}} - \frac {C x}{7 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} b} + \frac {8 \, C x}{105 \, \sqrt {b x^{2} + a} a^{3} b} + \frac {4 \, C x}{105 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{2} b} + \frac {C x}{35 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} a b} - \frac {128 \, A b x}{35 \, \sqrt {b x^{2} + a} a^{5}} - \frac {64 \, A b x}{35 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a^{4}} - \frac {48 \, A b x}{35 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} a^{3}} - \frac {8 \, A b x}{7 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}} a^{2}} - \frac {A}{{\left (b x^{2} + a\right )}^{\frac {7}{2}} a x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {A+B\,x^2+C\,x^4+F\,x^8+x^6\,D}{x^2\,{\left (b\,x^2+a\right )}^{9/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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